TP 8.40
Given:
m = 1.80 kg
Vi = 2.00 m/s, Vf = 0 m/s
xi = 0 m, xf = 0.110 m
mk = 0.560
Find: k - ?
Wnc= fk Dx cos(q) = mk n Dx cos(180o) = - mk m g Dx
Wnc= (Kf + Usf) - (Ki + Usi)
Kf = 0, Usi = 0
Wnc= Usf - Ki = 1/2 k xf2 - 1/2 m Vi2
- mk m g Dx = 1/2 k xf2 - 1/2 m Vi2
1/2 k xf2 = 1/2 m Vi2- mk m g Dx
k xf2 = m Vi2- 2 mk m g Dx
k = (m Vi2- 2 mk m g Dx)/ xf2
k = 415 N/m