TP 8.40

Given:

m = 1.80 kg

Vi = 2.00 m/s, Vf = 0 m/s

xi = 0 m, xf = 0.110 m

mk = 0.560

Find: k - ?

Wnc= fk Dx cos(q) = mk n Dx cos(180o) = - mk m g Dx

Wnc= (Kf + Usf) - (Ki + Usi)

Kf = 0, Usi = 0

Wnc= Usf - Ki = 1/2 k xf2 - 1/2 m Vi2

- mk m g Dx = 1/2 k xf2 - 1/2 m Vi2

1/2 k xf2 =  1/2 m Vi2- mk m g Dx

 k xf2 =  m Vi2- 2 mk m g Dx

k  =  (m Vi2- 2 mk m g Dx)/ xf2

k = 415 N/m