TP 4.57

                  Given:

x₀ = 0,  y₀ = 0.455 m, y = 0 (assuming that the origin of your coordinate system is located at the ground level)

q₀ = 60.5^o 

V₀ = 2.62 m/s                

                  Find: (a) t -  ?

V_x0 = V₀ cos(q₀) = (2.62 m/s) cos(60.5^o) = 1.29 m/s

V_y0 = V₀ sin(q₀) = (2.62 m/s) sin(60.5^o) = 2.28 m/s

 y = y₀ + V_0yt – ½ g t²

0 = y₀  + V_0yt – ½ g t²

½ g t² - V_0yt - y₀ = 0

t = (V_0y + (V_0y² - 4 (½ g)(- y₀))^1/2 )/(2 ( ½ g) )

t = (V_0y + (V_0y² + 2 g y₀)^1/2 )/g

t = 0.616 s

                            (b) x - ?

x = x₀ + V_x0 t

x = 0.795 m