TP 30.4

          Given:   T = 5800 K

 

           Find:   f peak- ?

 

f peak  = (5.88 x 1010 s-1K-1) T

f peak  = (5.88 x 1010 s-1K-1) (5800 K) =  3.41 x 1014 Hz (Compare the answer to the EM spectrum on page 826.)