TP 29.8

Given:   Dt0 = 2.60 x 10-8 s

              v = 0.99c

Find:   (a) Dt -?

Dt = Dt0 /(1-v2/c2)1/2

Dt = (2.60 x 10-8 s)  /(1-(0.99c)2/c2)1/2

Dt = 18.4 x 10-8 s

(b) L0 - ?

L0 = v Dt

L0 = (0.99c) (18.4 x 10-8 s) = 54.7 m  

(c) L = v Dt0

L = (0.99c) (2.60 x 10-8 s) = 7.72 m