TP 21.41
Given: R1 = 1.50 W
R2 = 2.50 W
R3 = 4.80 W
R4 = 3.30 W
R5 = 8.10 W
R6 = 6.30 W
DV = 9.00 V
(a) Find: I1, I2, I3, I4, I5, I6
From TP 21.37:
1/R345 = 1/R3 + 1/R4 + 1/R5
= 1/(4.80 W) + 1/(3.30 W) + 1/(8.10 W) =
0.634 W-1
R345 = 1.58 W
R3456 = R345 + R6 = 1.58 W +
6.30 W = 7.88 W
1/R12456 = 1/R1 + 1/R2 + 1/R3456
= 1/(1.50 W) + 1/(2.50 W) + 1/(7.88 W) =
1.19 W-1
R123456 = 0.838 W
Let’s start with resistor R1:
DV1
= I1 R1
I1
= DV1/ R1
= (9.00 V)/(1.50 W)
= 6.00 A
For resistor R2:
DV2
= I2 R2
I2
= DV2/ R2
= (9.00 V)/(2.50 W)
= 3.60 A
For the combination of resistors R3, R4, R5, and R6:
DV3456
= I3456 R3456
I3456
= DV3456/ R3456
= (9.00 V)/(7.88 W)
= 1.14 A
Notice: it is a series combination of R345 and R6:
I6 = I3456 = 1.14 A
also, DV6 = I6 R6 = (1.14 A) (6.30 W) = 7.20 V
DV3
= DV4 = DV5 = 9.00 V - 7.20 V = 1.80 V
For resistor R3:
DV3
= I3 R3
I3
= DV3/ R3
= (1.80 V)/(4.80 W)
= 0.375 A
For resistor R4:
DV4
= I4 R4
I4
= DV4/ R4
= (1.80 V)/(3.30 W)
= 0.545 A
For resistor R5:
DV5
= I5 R5
I5
= DV5/ R5
= (1.80 V)/(8.10 W)
= 0.222 A
(b)
Less, see (a)