MIME-Version: 1.0 Content-Type: multipart/related; boundary="----=_NextPart_01CB2E43.9008BF50" This document is a Single File Web Page, also known as a Web Archive file. If you are seeing this message, your browser or editor doesn't support Web Archive files. Please download a browser that supports Web Archive, such as Windows® Internet Explorer®. ------=_NextPart_01CB2E43.9008BF50 Content-Location: file:///C:/D9286902/Summer10.phys1112.exam1.SolutionWeb.htm Content-Transfer-Encoding: quoted-printable Content-Type: text/html; charset="us-ascii" TIME OF COMPLETION_______________

TIME OF COMPLETION_______________&n= bsp;          NAME___SO= LUTION__________________________

 

 

<= span style=3D'mso-bidi-font-size:10.0pt'> &= nbsp;           &nbs= p;            &= nbsp;           &nbs= p;  DEPARTMENT OF NATURAL SCIENCES

 

PHYS 1112, Exam 1            =             &nb= sp;            =             &nb= sp;            =             &nb= sp;            =             &nb= sp;       Section 1

Version 1            &= nbsp;           &nbs= p;            &= nbsp;           &nbs= p;            &= nbsp;           &nbs= p;            &= nbsp;           &nbs= p;            &= nbsp;     June 17, 2010

Total Weight: 100 points

 

1.     &nb= sp;   Check your examination for completeness prior to starting.  There are a total of ten (10) prob= lems on seven (7) pages.

 

2.   =       Authorized references include your calculator with calculator handbook, and the Refere= nce Data Pamphlet (provided by your instructor).

 

3.     &nb= sp;   You will have 125 minutes to complete the examination.

 

4.     &nb= sp;   The total weight of the examination is 150 points.

 

5.     &nb= sp;   There are six (6) multiple choice and four (4) calculation problems. Work six (6)= multiple choice problems and four (4) calculation problems. Show all work; partial credit will be given for correct work shown.

 

6.     &nb= sp;   If you have any questions during the examination, see your instructor who will=

be located in the classroom.

 

7.     &nb= sp;   Start:        &= nbsp;      10:15 a.m.

Stop:&n= bsp;            = ;   12:20 p.m.

 

 

 

 = ;             <= /span>PROBLEM

 

 = ;            &n= bsp;   POINTS

 

 = ;            &n= bsp;  CREDIT

 

     &nb= sp;            =    1-6

 

     &nb= sp;            =     30

 

 = ;

 

     &nb= sp;            =      7

 

     &nb= sp;            =     30

 

 = ;

 

8

 

     &nb= sp;            =     30

 

 = ;

 

     &nb= sp;            =      9

 

     &nb= sp;            =     30

 

 = ;

 

 = ;            &n= bsp;        10<= /p>

 

 = ;            &n= bsp;        30<= /p>

 

 

 

 = ;            &n= bsp;   TOTAL

 

 = ;            &n= bsp;       150

 

 

 

 

 

 = ;         PERCENTAGE

 

 

 

CIRCLE THE SINGLE BEST ANSWER FOR ALL MULTIPLE CHOICE QUESTIONS. IN MULTIPLE CHOICE QUESTIONS WHICH REQUIRE A CALCULATION SHOW WORK FOR PARTIAL CREDIT.

 
 
 


Questions 1-3 refer to the map of equipotential surfaces

shown below.

 

1. Direction of the electric fi= eld at point A is toward  =

            = (A) Point B.

            = (B) Point C.=

(5)        (C) Point D.

            = (D) Point E.

 &nb= sp;          (E) Infinity.

 

 

2.  A negative charge is moved from po= int A to point B.

            = (A) The negative charge performs work in moving from point A to point B.=

            = (B) Work is required to move the negative charge from point A to point B.

(5)        (C) Work is both required and performed in moving the negative charge from poin= t A to

        =            point B.

            = (D) No work = is required to move the negative charge from point A to point B.

        &= nbsp;   (E) None of the above choices is correct.

 

 

3.  A charge of 3.00 mC is moved from point C to poi= nt D. How much work was required to move the charge?

            = (A) 50.0 mJ.

            = (B) 50.0 mV.

(5)        (C) 150 m<= /span>J.

            = (D) 150 mV.

            = (E) -150 mJ.

 

 

4.  When two or more capacitors are connected in series to a battery,

            = (A) The total voltage across the combination is the algebraic sum of the voltag= es across

        =           the individual capacitors.

            = (B) Each capacitor carries the same amount of charge.

(5)        (C) The equivalent capacitance of the combination is less than the capacitance = of any of

        =            the capacitors.

            = (D) All of t= he given answers are correct.

        &= nbsp;   (E) None of the above answers is correct.

 

 

5. Three 10.0 mF capacitors a= re connected in parallel with the potential difference of 9.00 V across the combination. The capacitors are then rearranged to form a series combinatio= n. If the same potential difference of 9.00 V was maintained across the combination, the total charge on the combination

 

(A)  Increased.

 

(B)   Decreased.

(5)

(C)   Remained the same.

 

(D)  Impossible to say without knowing the charge on = one of the capacitors.

 

(E)   Become zero.

 

 

6. A negative charge, if free, tries to move

 

  &nbs= p;         (A) From high potential to low potential.

 

  &nbs= p;         (B) From low potential to high potential.

 

(5)  &= nbsp;     (C) Toward Infinity.

 

  &nbs= p;         (D) Away from infinity.

 

(F)    In the direction of the electric field

 

 

 

  1. Five identical 2.00 <= /span>mF capacitors are connected as shown below.

 

a. Find equivalent capacitance of the network.

Q

b. If a potential difference of 12.0 V is applied between points a and b, how much charge is stored on Capacitor 1?<= /p>

 

c. What is the potential difference across the Capacitor 4= ?

8.  Determine the electric field <= !--[if gte vml 1]>  at the orig= in 0 due to the three charges pictured below. Specify magnitude and direction. L= et Q =3D 7.50 mC and l =3D 0.350 m.

 

E1 =3D k |q1|/r12 =3D (8.99 x 109 N-m2/C2) (7.50 x 10-6= C) / (0.350 m)2 =3D 5.50 x 105 N/C @ -90o<= /p>

 

E2 =3D k |q2|/r22 =3D (8.99 x 109 N-m2/C2) (7.50 x 10-6= C) / (0.495 m)2 =3D 2.75 x 105 N/C @ 225o<= /p>

 

E3 =3D k |q3|/r32 =3D (8.99 x 109 N-m2/C2) (7.50 x 10-6= C) / (0.350 m)2 =3D 5.50 x 105 N/C @ 0o

 

 

E1x =3D E= 1 cos(- 90o) =3D 0

 

E1y =3D E= 1 sin(- 90o) =3D - 5.50 x 105 N/C

 

E2x =3D E= 2 cos(225o) =3D - 1.94 x 105 N/C

 

E2y =3D E= 2 sin(225o) =3D - 1.94 x 105 N/C

 

E3x =3D E= 3 cos(0o) =3D 5.50 x 105 N/C

 

E3y =3D E= 3 sin(0o) =3D 0

 

 

Etot x =3D E1x + E2x + E3x =3D   3.56 x 105 N/C

 

Etot y =3D E1y + E2y+ E3y =3D - 7.44 x 105 N/C=

 

 

Etot  =3D 8.25 x 105 N/C

 

q =3D -64.4o

 

 

 

9.   Deter= mine the electric potential V at the origin 0 due to the three charges pictured below. Let Q =3D 7.50 mC and= l =3D 0.350 m.

 

V1 =3D k q1/r1 =3D (8.99 x 109 N-m2/C2) (7.50 x 10-6= C) / (0.350 m) =3D 1.93 x 105 V

 

V2 =3D k q2/r2 =3D (8.99 x 109 N-m2/C2) (7.50 x 10-6= C) / (0.495 m) =3D 1.36 x 105 V

 

V3 =3D k q3/r3 =3D (8.99 x 109 N-m2/C2) (-7.50 x 10-= 6 C) / (0.350 m) =3D - 1.93 x 105 V

 

Vtot =3D V1 + V2 + V3 =3D 1.36 x 105= V

 

Bonus (10 points): How much= work needs to be done to move another charge of=   –7.50 m<= /span>C from infinity to the origin 0?

 

W =3D qVtot =3D ((-7.50 x 10-6 C)( 1.36 x 105 <= /sup>V) =3D -1.02 J

 

 

10. The spacing between the plates of 1.00 mF parallel plate capacitor is 0.070= 0 mm.

 

  1. What = is the surface area of the plates?

 

 

 

 

  1. How m= uch charge is on the plates if this capacitor is attached to a 1.50 V batt= ery?

 

 

 

 

  1. How much work did the battery perform while charging the capacitor?

 

 

 

 

 

 

 

 

 

 

 

 

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PHYS 1112 Exam 1, Version 1

Summer 2010        =             &nb= sp;            =             &nb= sp;            =             &nb= sp;    8

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