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<p class=3DMsoNormal align=3Dcenter style=3D'text-align:center'><st1:place =
w:st=3D"on"><st1:PlaceName
 w:st=3D"on">Clayton</st1:PlaceName> <st1:PlaceName w:st=3D"on">State</st1:=
PlaceName>
 <st1:PlaceType w:st=3D"on">University</st1:PlaceType></st1:place></p>

<p class=3DMsoNormal align=3Dcenter style=3D'text-align:center'>Department =
of Natural
Sciences</p>

<p class=3DMsoNormal align=3Dright style=3D'text-align:right'><o:p>&nbsp;</=
o:p></p>

<p class=3DMsoNormal align=3Dright style=3D'text-align:right'>February 21, =
2008</p>

<p class=3DMsoNormal align=3Dcenter style=3D'text-align:center'>Physics 111=
2 &#8211;
Quiz 5</p>

<p class=3DMsoNormal align=3Dcenter style=3D'text-align:center'><o:p>&nbsp;=
</o:p></p>

<p class=3DMsoNormal align=3Dcenter style=3D'text-align:center'><span
style=3D'mso-spacerun:yes'>&nbsp;</span></p>

<p class=3DMsoNormal><span class=3DGramE>Name<span style=3D'mso-spacerun:ye=
s'>&nbsp;
</span>_</span>___SOLUTION_________________________________</p>

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</span></p>

<p class=3DMsoNormal style=3D'text-align:justify'>Given the network, write
equations that would allow you to solve for the currents in each resistor if
the values of the <span class=3DSpellE>emfs</span> and resistances were kno=
wn.
Label and indicate your choices for current directions. DO NOT SOLVE THE
EQUATIONS.</p>

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style=3D'mso-spacerun:yes'>&nbsp; </span></p>

<p class=3DMsoNormal style=3D'margin-left:24.1pt;text-indent:-24.1pt;mso-pa=
gination:
widow-orphan no-line-numbers'>Junction rule:</p>

<p class=3DMsoNormal style=3D'margin-left:24.1pt;text-indent:-24.1pt;mso-pa=
gination:
widow-orphan no-line-numbers'><o:p>&nbsp;</o:p></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span style=3D'mso-bidi-f=
ont-size:
10.0pt'>0 =3D I<sub>1</sub> + I<sub>2 </sub></span>+ <span style=3D'mso-bid=
i-font-size:
10.0pt'>I<sub>3<o:p></o:p></sub></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><sub><span style=3D'mso-b=
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ub></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span style=3D'mso-bidi-f=
ont-size:
10.0pt'>Loop rule, upper loop, clockwise<o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span style=3D'mso-bidi-f=
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<p class=3DMsoNormal style=3D'text-align:justify'><span style=3D'mso-bidi-f=
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0.0pt'>1</span></sub><span
style=3D'mso-bidi-font-size:10.0pt'> &#8211; I<sub>1</sub> R<sub>3 </sub>+ =
I<sub>3</sub>
R<sub>4<span style=3D'mso-spacerun:yes'>&nbsp; </span><span
style=3D'mso-spacerun:yes'>&nbsp;</span></sub>+<sub> </sub></span><span
style=3D'mso-bidi-font-size:10.0pt;font-family:Symbol'>e</span><sub><span
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10.0pt'>Loop rule, lower loop, counterclockwise<o:p></o:p></span></p>

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idi-font-size:
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<p class=3DMsoNormal style=3D'text-align:justify'><span style=3D'mso-bidi-f=
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0.0pt'>2</span></sub><span
style=3D'mso-bidi-font-size:10.0pt'> &#8211; I<sub>2</sub> R<sub>1 </sub>+ =
</span><span
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style=3D'mso-bidi-font-size:10.0pt'>3</span></sub><span style=3D'mso-bidi-f=
ont-size:
10.0pt'> &#8211; I<sub>2</sub> R<sub>5<span
style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span></sub>+ I<sub>3</sub> R<sub>=
4 </sub>=3D
0<sub><span style=3D'mso-spacerun:yes'>&nbsp;&nbsp; </span><o:p></o:p></sub=
></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><sub><span style=3D'mso-b=
idi-font-size:
10.0pt'><o:p>&nbsp;</o:p></span></sub></p>

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</span></p>

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