MIME-Version: 1.0 Content-Type: multipart/related; boundary="----=_NextPart_01C788FC.BBE6A6E0" This document is a Single File Web Page, also known as a Web Archive file. If you are seeing this message, your browser or editor doesn't support Web Archive files. Please download a browser that supports Web Archive, such as Microsoft Internet Explorer. ------=_NextPart_01C788FC.BBE6A6E0 Content-Location: file:///C:/D9286902/Spring07.phys1112.exam3.SolutionWeb.htm Content-Transfer-Encoding: quoted-printable Content-Type: text/html; charset="us-ascii" TIME OF COMPLETION_______________

 TIME OF COMPLETION_______________   =          NAME___SOLUTION____= ______________________

 

 

<= span style=3D'mso-bidi-font-size:10.0pt'> &= nbsp;           &nbs= p;            &= nbsp;           &nbs= p;    DEPARTMENT OF NATURAL SCIENCES

 

PHYS 1112, Exam 3            =             &nb= sp;            =             &nb= sp;            =             &nb= sp;            =             &nb= sp;  Section 1

Version 1            &= nbsp;           &nbs= p;            &= nbsp;           &nbs= p;            &= nbsp;           &nbs= p;            &= nbsp;           &nbs= p;          April 24, 2007

Total Weight: 100 points

 

1.     &nb= sp;   Check your examination for completeness prior to starting.  There are a total of ten (10) prob= lems on eight (8 ) pages.

 

2.   =       Authorized references include your calculator with calculator handbook, and the Refere= nce Data Pamphlet (provided by your instructor).

 

3.     &nb= sp;   You will have 75 minutes to complete the examination.

 

4.     &nb= sp;   The total weight of the examination is 100 points.

 

5.     &nb= sp;   There are six (6) multiple choice and four (4) calculation problems. Work all problems.  Show all work; part= ial credit will be given for correct work shown.

 

6.     &nb= sp;   If you have any questions during the examination, see your instructor who will=

be located in the classroom.

 

7.     &nb= sp;   Start:        &= nbsp;      10:30 a.m.

Stop:&n= bsp;            = ;   11:45 a.m.

 

 

 

 = ;             <= /span>PROBLEM

 

 = ;            &n= bsp;   POINTS

 

 = ;            &n= bsp;  CREDIT

 

     &nb= sp;            =    1-6

 

     &nb= sp;            =    20

 

 = ;

 

     &nb= sp;            =     7

 

     &nb= sp;            =    20

 

 = ;

 

8

 

     &nb= sp;            =    20

 

 = ;

 

     &nb= sp;            =     9

 

     &nb= sp;            =    20

 

 = ;

 

 = ;            &n= bsp;       10

 

 = ;            &n= bsp;       20

 

 

 

 = ;            &n= bsp;   TOTAL

 

 = ;            &n= bsp;      100

 

 

 

 

 

 = ;          PERCENTAGE

 

 

 

CIRCLE THE SINGLE BEST ANSWER FOR ALL MULTIPLE CHOICE QUESTIONS. IN MULTIPLE CHOICE QUESTIONS WHICH REQUIRE A CALCULATION SHOW WORK FOR PARTIAL CREDIT.

 

 

 

 

 

1.  Light arriving at a concave mirror on a path through the center of curvature is reflected

 

  &nbs= p;         a. Back parallel to the axis.

 

  &nbs= p;         b. Back on itself.

(4)

  &nbs= p;         c. Through the focal point.

 

  &nbs= p;         d. Midway between the focal point and the center of curvature.

 

 

2.  An object is placed at a concave mirror's center of curvature.  The image produced by the mirror is located

 

  &nbs= p;         a. Out beyond the center of curvature.

 

  &nbs= p;         b. At the center of curvatur= e.

(4)

  &nbs= p;         c. Between the center of curvature and the focal point.

 

  &nbs= p;         d. At the focal point.

 

 

 

3.  Concave spherical mirrors produce images which

 

  &nbs= p;         a. Are always smaller than the actual object.

 

  &nbs= p;         b. Are always larger than the actual object.

(4)

  &nbs= p;         c. Are always the same size as the actual object.

 

  &nbs= p;         d. Could be smaller than, la= rger than, or the same size as the actual object, depending on the placement of = the object.

 

 

 

 

 

 

 

4.  Light enters air from water.  The an= gle of refraction will be=

 

  &nbs= p;         a. Greater than the angle of incidence.

(4)

  &nbs= p;         b. Equal to the angle of incidence.

 

  &nbs= p;         c. Less than the angle of incidence.

 

 

 

5.  Lenses that are thicker at the center

 

  &nbs= p;         a. Spread out light rays.

 

  &nbs= p;         b. Bend light rays to a point beyond the lens.

(4)

  &nbs= p;         c. Have no effect on light rays.

 

  &nbs= p;         d. Reflect light rays back.

 

 

 

6.     Radio, microwaves, infrared radiation, and visib= le light are

 

a.      Portions of the electromagnetic spectr= um.

 

b.     Portions of the electromagnetic spectrum, except= radio waves which are not.

(4)

c.       Po= rtions of the electromagnetic spectrum, except radio and micro waves which are not= .

 

d.       Portions of the electromagnetic spectrum, except infrared radiation which is not.

 

 

7. An object is 1= 6.0 cm to the left of the lens. The lens forms an image 36.0 cm to the right of= the lens.

a. What is the fo= cal length of the lens?

do=3D 16.0 cm

 

di=3D 36.0 cm

 

1/di + 1/do=3D 1/f

 

1/f =3D 1/(16.0 cm) + 1/(36.0 cm) =3D  0.0903 cm-1

 

f =3D 11.1 cm

 

b. Is the lens converg= ing or diverging?

Converging (f > 0)

c. If the object is 8.= 00 cm tall, how tall is the image?

M =3D - di /do =3D -2.25

 

hi=3D M= ho=3D -18.0 mm=

d. Is it upright or inverted?

Inverted (M < 0)

e. Draw a ray diagram.=

 

8.     An object 9.00 mm tall= is placed 12.0 cm to the left of the vertex of a convex spherical mirror whose radius of curvature has a magnitude of 20.0 cm.

a. Determine the position of the image.<= /p>

do=3D 12.0 cm

 

f =3D - 10.0 cm

 

1/di + 1/do=3D 1/f

 

1/di =3D 1/f - 1/do 

 

1/ di =3D 1/(-10.0 cm) - 1/(12.0 cm) =3D  0.183 cm-1

 

di =3D -5.45 cm

 

b. How tall is the image?

 

M =3D - di /do =3D 0.455

 

hi=3D M= ho=3D 4.09 mm=

 

c. Is the image real or virtual?

 

Virtual (di <0)

 

d. Is the image upright or inverted?

 

Upright (M > 0)

 

9.&n= bsp;    An object 10.00 = cm high is placed 12.0 cm to the left of the converging lens of focal length 8= .00 cm. A second converging lens of focal length of 6.00 cm is placed 36.0 cm to the right of the first lens on the same principal axis. <= /p>

 

 

 

= a.      Where is the image produced by the combination located?

 

1st Lens:

do1=3D 12.0 cm

 

f1 =3D 8.00 cm

 

1/di1 + 1/do1=3D 1/f1=

 

1/di1 =3D 1/f1 - 1/do1 

 

1/ di1 =3D 1/(8.00 cm) - 1/(12.0 cm) =3D  0.0417 cm-1

 

di1 =3D 24.0 cm <= /span>

 

M1 =3D - di1 /do1 =3D= - 2.00

 

2nd  Lens:

do2=3D 36.0 cm – 24.0 cm =3D 12.0 cm<= /p>

 

f2 =3D 6.00 cm

 

1/di2 + 1/do2=3D 1/f2=

 

1/di2 =3D 1/f2 -  1/do2 

 

1/ di2 =3D 1/(6.00 cm) - 1/(12.0 cm) =3D  0.0833 cm-1

 

di2 =3D 12.0 cm <= /span>

 

M2 =3D - di2 /do2 =3D= -1.00

 

= b.     How high is it?

 

M =3D M1 M2 =3D (-2.00)(-1.00) = =3D 2.00

 

hi=3D M= ho=3D 20.0 cm=

 

c. Is the image upright or inverted?

 

 Upright (M > 0)

 

 

 

10.  You have a 200-W resistor, a 0.400-H inductor, and a 6.= 00-mF capacitor. They are connected in seri= es with an ac source of peak voltage of 30.0 V operating at 100 Hz frequency. =

 

a. What is the impedance of the circuit= ?

 

XL =3D 2 p f L =3D 2 p (100 Hz) (0.400 H) =3D 251 W

 

XC =3D 1/(2 p f C) =3D 1/(2 p (100 Hz) (6.00 x 10-6 F)) =3D 265 W

 

Z =3D (R2 + (X<= sub>L – XC)2)1/2  =3D 200 = W

 

 

b. What is the rms current flowing in t= he resistor?

 

DVrms =3D DVmax/(2)1/2<= /sup> =3D 21.2 V

 

Irms =3D DVrms/Z =3D (21.2 V)/(200 W) =3D 0.106 = A

 

      = ;     

c. What is the rms pot= ential drop across the resistor?

DVR, rms =3D Irms R =3D (0.106 A)(200 W) =3D 21.2 V

 

d. What is the rms power dissipated by = the circuit?

 

Prms =3D Irms DVR, rms =3D (0.106 A)(21.2 V) =3D 2.25 W=

 

 

e. At this frequency, will the voltage = lead or lag the current?

 

tan f =3D (XL – XC)/R =3D (251 W - 265 W)/(200 W)

 

f =3D -4.00o Voltage lags the current.

 

 

 

------=_NextPart_01C788FC.BBE6A6E0 Content-Location: file:///C:/D9286902/Spring07.phys1112.exam3.SolutionWeb_files/header.htm Content-Transfer-Encoding: quoted-printable Content-Type: text/html; charset="us-ascii"

 

 

PHYS 1112 Exam 3, Version 1

Spring 2007        =             &nb= sp;            =             &nb= sp;            =             &nb= sp;    9

------=_NextPart_01C788FC.BBE6A6E0 Content-Location: file:///C:/D9286902/Spring07.phys1112.exam3.SolutionWeb_files/oledata.mso Content-Transfer-Encoding: base64 Content-Type: application/x-mso 0M8R4KGxGuEAAAAAAAAAAAAAAAAAAAAAPgADAP7/CQAGAAAAAAAAAAAAAAABAAAAAQAAAAAAAAAA EAAAAgAAAAEAAAD+////AAAAAAAAAAD///////////////////////////////////////////// //////////////////////////////////////////////////////////////////////////// //////////////////////////////////////////////////////////////////////////// //////////////////////////////////////////////////////////////////////////// //////////////////////////////////////////////////////////////////////////// //////////////////////////////////////////////////////////////////////////// //////////////////////////////////////////////////////////////////////////// ///////////////////////////////////////////////////////////////////////////9 /////v////7///8EAAAABQAAAAYAAAD+//////////////////////////////////////////// //////////////////////////////////////////////////////////////////////////// //////////////////////////////////////////////////////////////////////////// //////////////////////////////////////////////////////////////////////////// //////////////////////////////////////////////////////////////////////////// //////////////////////////////////////////////////////////////////////////// //////////////////////////////////////////////////////////////////////////// //////////////////////////////////////////////////////////////////////////// /////////////////////////////////////////////////////////////////////////1IA bwBvAHQAIABFAG4AdAByAHkAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA AAAAAAAWAAUA//////////8BAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAGCWCkMeiccB AwAAAIAHAAAAAAAAXwAxADIAMwA5ADIAMAA0ADkAMQA5AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA AAAAAAAAAAAAAAAAAAAAAAAAABgAAgH/////AgAAAP////8AAAAAAAAAAAAAAAAAAAAAAAAAAAAA AAAAAAAAAAAAAAAAAAAAAAAAuQMAAAAAAABfADEAMgAzADkAMgAwADQAOQAyADAAAAAAAAAAAAAA AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAGAACAP///////////////wAAAAAAAAAA AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA8AAAC5AwAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA//////// ////////AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAQAA AAIAAAADAAAABAAAAAUAAAAGAAAABwAAAAgAAAAJAAAACgAAAAsAAAAMAAAADQAAAA4AAAD+//// EAAAABEAAAASAAAAEwAAABQAAAAVAAAAFgAAABcAAAAYAAAAGQAAABoAAAAbAAAAHAAAAB0AAAD+ //////////////////////////////////////////////////////////////////////////// //////////////////////////////////////////////////////////////////////////// //////////////////////////////////////////////////////////////////////////// //////////////////////////////////////////////////////////////////////////// //////////////////////////////////////////////////////////////////////////// //////////////////////////////////////////////////////////////////////////// //////////////////////////////////////////////////////////////////////8AEAAA eJztVs1rE0EUf5tNWhtNu9FatX6weNBLEretFo0i0lpFRA1VqMduzKYdzX64WY2pWKoHQfDgUUEE /QOkFg/iSbx41IMHj3oUPIkHLya+mZ3djCFqU4si9IXJ/nbmzbw3b97+5r15nXz/8En/B2iSgyBD rd4FHUKfxBsTBSDC32v1ej3orq/IfyXfsHXwM4ziM8Zx7R/7tSJ/R8bBxp8HKoyBhU8Xqs1U8Evp w4wJ1qJ8MFnLHLq3abNy73E0sgWciKg7qddGtt16JcmID8UCTjkFJTDasilKHCKSuJ/FzuvlTxkm IAdHYRC0JdnvRvuUA+m3s1j7jEOjAR7F+JvgYBzycL5t+2uRhdvdfxKbw3GNn5vMXaLHQvmgE9sq bF1AYwywGtsabAmgewboAXYFsPlrocEZK7zxfwnmYmRVU364Z4wr3sFEXFUPVLKjtunoHsmTEvGq rJP2njZKxjlvzPLqE7nRfprHff6nTvPoNkNRqWPDfHTez/OUlGKfPRUJZBmSd4be7ZTgbMT/Ya8c ZQmFqgDBU47RZEtJUQj+5T207JAHfNoBeR/E/M9JYJqEULSs4Xgv4ziAm8hw1ExUcTHfb8CzTjYb xxz4yjRVuBDOV6Ek4Liwbiqwh8GbTDZ0dgv6ewQ8zLFve7bFXIAdwh6GW64PcFzwwepopYN2oYEP tNTBcPP1vyL7znG/IhiTwMeYcjPE3cqDEK9XXoa4S/kc4n5lhxTgrcqRsEz8nczBNDuXWShyH4rI zTPwlJ1LL46dRQ//jpTgDmYJFRVs4exeCDgjxH+XgB93ctAU5wFBZ1DAQxx7cBfegh+3HmUhHP8k 6D7qbOCHAp4VdOYE7Aj4+k9y5D5fh9pNKs9b+r6+AeHjz/IImV+O+3df891PeSHnGmXD8pBBbKus DmU09bCrV4g1xW6SMTNvFNTT9iX3nMGupYkcHR7SMoHWl30LFwU3IKMRS3XJ1LSnDlNMGadoW166 TGaM7MBgRnO8/Yl4F+sr6iYpVbPbzxDTKKsnjYo6bpu6tZ0qmGUbx12aqNSTjcKzSflaIu5kTpTt EbtQpcyYUkvkx/cCuSx24OpXTd2dIlYWPWTG2Fs6b3uebWYzmqYN+G56qJ7WS2TKyp6/VPZIsRr4 5ug4g4UtWyEFu5K2XWdat8K9Ne2XTsmTAkkLg9oigiHzuuMYVn9FrETaFaw/GLHTuoHmwGLmrIOw /MHTG+EVYA505GavTfu9S6h/eqFR/y2HtGt/ueVP7H8H6l+Y+G4gcmlnaHQAEAAAeJztVs1rE0EU f5tNWhuNbrR+1Q8WD3pJ4rbVYmMppbWKiBpaoR7dmE07mv1wsxqjWKqHguChRwUR9A8QFQ/iSbx4 1IMHj3pT8CQeejHxzezsZgxRGxVF6AuT/e3Mm3lv3rz9zXv1Mvn27sOed9AkwyBDrd4FHUKfxBsT BSDC32v1ej3ori/LfyVfsHXwM4ziM8Zx7R/7tSx/RybAxp8HKoyDhU8Xqs1U8EPZgBkTrEX54FQt M3Jr8xbl1v1oZCs4kW+U39dHt19/IckIR2IBpxyHEhht2RQlDhFJ3M9S53XzpwxTkIND0AfaL9lf jfYpB9JvZ6n2GYdGAzyG8TfBwTjk4Uzb9tciC7e7/yQ2h+MaPzeZu0SPhfJBJ7YV2LqAxhhgJbZV 2BJA9wywBtgVwOavhQZnLPPG/yWYi5EVTfnhnjAuesOJuKoOVbJjtunoHsmTEvGqrJP2Thol47Q3 bnn1qdxYD83jDf6nTvPoBkNRqWPjg+gDP89TUop99lQkkGVILvS/2SXByYj/w145yhIKVQGCpxyj yZaSohD8y3tp2SH3+rQD8iDE/M9JYJqEULSs4ngf4ziAeWQ4aiaquJjv1+BJJ5uNYw4sMk0Vzobz VSgJOC6smwrsYfBOJRs6ewT9vQIe4Ni3PdtiLsBOYQ8DLdcHOCL4YHW00kG70MBDLXUw3Hz9RWTf Oe5XBGMS+BhT5kO8WrkT4vXK8xB3KZ9C3KPslAK8TTkYlok/kzmYYecyC0XuQxG5+RI8ZufSjWMn 0cO/IyVYwCyhooItnN0zAWeE+O8W8P1ODpri3Cvo9Am4n2MPbsJr8OO2RnkUjn8UdO91NvBdAc8K OnMCdgR89Ts5cpuvQ+0mlactfV/fgPDhe3mEzC/H/buv+e6nvJBzjbJhecggtlVW+zOaesDVK8Sa ZjfJuJk3Cuqkfd49bbBraSpHh/u1TKD1efDROcENyGjEUl0yPeOpAxRTxinalpcuk0tGtrcvozne /kS8i/UVdZOUqtkdJ4hplNVjRkWdsE3d2kEVzLKN4y5NVOrJJuHZpHwlEXcyR8v2qF2oUmZMqSXy 7XuBXBA7cPXLpu5OEyuLHjJj7C2dtz3PNrMZTdN6fTc9VE/rJTJtZc+cL3ukWA18c3ScwcKWrZCC XUnbrjOjW+HemvZLp+RJgaSFQW0JwZB53XEYq78iViLtCtYfjNhp3UBzYClz1kFY/uDpjfIKMAc6 crPXpv3uX6h/uqFR//0Jadf+n5bfsf8VuRSZIJmNIDcuN3B0IDBpbiA3LjdwdCc+DQogIDxwIGNs YXNzPU1zb05vcm1hbCBzdHlsZT0nbGluZS1oZWlnaHQ6OC4xNXB0O21zby1saW5lLWhlaWdodC1y dWxlOmV4YWN0bHknPjxzcGFuDQogIHN0eWxlPSdtc28tYmlkaS1mb250LXNpemU6MW== ------=_NextPart_01C788FC.BBE6A6E0 Content-Location: file:///C:/D9286902/Spring07.phys1112.exam3.SolutionWeb_files/image001.wmz Content-Transfer-Encoding: base64 Content-Type: application/x-ms-wmz H4sIAAAAAAACC7t+9tgsBob/9f/rGRsYG/gYQEA+nJGBk4GBWR3IZmTgAIuxAjE3E0gdiMXDxMTA BBZjY2QEkiA1v5hYGRgZIIAFiHWBHGYIFwCbBorkZQAAAA== ------=_NextPart_01C788FC.BBE6A6E0 Content-Location: file:///C:/D9286902/Spring07.phys1112.exam3.SolutionWeb_files/image003.gif Content-Transfer-Encoding: base64 Content-Type: image/gif R0lGODlhDgAOAHcAMSH+GlNvZnR3YXJlOiBNaWNyb3NvZnQgT2ZmaWNlACH5BAEAAAAALAAAAAAB AAEAgAAAAAECAwICRAEAOw== ------=_NextPart_01C788FC.BBE6A6E0 Content-Location: file:///C:/D9286902/Spring07.phys1112.exam3.SolutionWeb_files/filelist.xml Content-Transfer-Encoding: quoted-printable Content-Type: text/xml; charset="utf-8" ------=_NextPart_01C788FC.BBE6A6E0--