Department of Natural Sciences
Clayton College & State University
February 10, 2003
Physics 1112 – Quiz 4b
Name ____SOLUTION_________________________________
R = r L/ A = (3500 x 10-8 W-m) (0.0300 m) / (0.005 m x 0.005 m) = 0.0420 W
I = DV/R = (8.40 V) / (0.0420 W) = 200A
P = I DV = (200 A) (8.40 V) = 1680 W
E = P DT = (168 W) (1.00 s) = 1680 J