Department of Natural Sciences
Clayton College & State University
February 10, 2003
Physics 1112 – Quiz 3a
Name _____SOLUTION________________________________

R = R1 + R2
R1 = r1 L2/ A = (4.00 x 10-3 W-m) (0.250 m) / (0.003 m x 0.003 m) = 111 W
R2 = r2 L2 / A = (6.00 x 10-3 W-m) (0.400 m) / (0.003 m x 0.003 m) = 267 W
R = 111 W + 267 W = 378 W
P = V2/R = (120 V)2 / (378 W) = 38.1 W
E = P DT = (38.1 W) (1.00 s) = 38.1 J