Clayton College & State University
Department of Natural Sciences
March 12, 2003
Physics 1112 – Quiz 6b
Name ________SOLUTION_____________________________

e = V
B L = (5.00 m/s)(0.110 T) (1.00 m) = 0.550 V
I = e/R = (0.0550 V)/(30.0 W) = 0.0183 A
F = I L B = (0.0183 A) (1.00 m) (0.110 T) = 0.00202
N
The direction of the current induced in the circuit
is counterclockwise.