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</o:p></p>

<p class=3DMsoNormal align=3Dcenter style=3D'text-align:center'><o:p>&nbsp;=
</o:p></p>

<p class=3DMsoNormal align=3Dcenter style=3D'text-align:center'><o:p>&nbsp;=
</o:p></p>

<p class=3DMsoNormal align=3Dcenter style=3D'text-align:center'>Department =
of Natural
Sciences</p>

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w:st=3D"on"><st1:PlaceName
 w:st=3D"on">Clayton</st1:PlaceName> <st1:PlaceName w:st=3D"on">State</st1:=
PlaceName>
 <st1:PlaceType w:st=3D"on">University</st1:PlaceType></st1:place></p>

<p class=3DMsoNormal align=3Dcenter style=3D'text-align:center'><o:p>&nbsp;=
</o:p></p>

<p class=3DMsoNormal align=3Dright style=3D'text-align:right'>October 31, 2=
008</p>

<p class=3DMsoNormal align=3Dcenter style=3D'text-align:center'>Physics 221=
1 &#8211;
Quiz 9</p>

<p class=3DMsoNormal align=3Dcenter style=3D'text-align:center'><o:p>&nbsp;=
</o:p></p>

<p class=3DMsoNormal align=3Dcenter style=3D'text-align:center'><o:p>&nbsp;=
</o:p></p>

<p class=3DMsoNormal><span class=3DGramE>Name<span style=3D'mso-spacerun:ye=
s'>&nbsp;
</span>_</span>__SOLUTION_________________________________</p>

<p class=3DMsoNormal><o:p>&nbsp;</o:p></p>

<p class=3DMsoNormal>A 2.00 kg piece of wood slides on the surface shown be=
low.
The curved sides are perfectly smooth, but the rough horizontal bottom is 1=
0.0
m long and has a coefficient of kinetic friction with the wood of 0.200. The
piece of wood starts from rest 4.00 m above the rough bottom.</p>

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<p class=3DCRPROB align=3Dleft style=3D'text-align:left;mso-pagination:none=
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lang=3DEN-AU style=3D'font-size:12.0pt;line-height:200%'><o:p>&nbsp;</o:p><=
/span></p>

<p class=3DCRPROB align=3Dleft style=3D'text-align:left;mso-pagination:none=
'><span
lang=3DEN-AU style=3D'font-size:12.0pt;line-height:200%'>a.<span
style=3D'mso-spacerun:yes'>&nbsp; </span>Find the magnitude of the kinetic
friction that acts on the wood as it moves over the rough bottom. <o:p></o:=
p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><span class=3DSpellE><span
class=3DGramE>f<sub>k</sub></span></span><sub> </sub>=3D <span style=3D'fon=
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Symbol'>m</span><sub>k </sub><span style=3D'mso-spacerun:yes'>&nbsp;</span>=
n =3D <span
style=3D'font-family:Symbol'>m</span><sub>k</sub>(mg)<sub> </sub><span
style=3D'mso-spacerun:yes'>&nbsp;</span>=3D (0.200)(2.00 kg)(9.80 m/s<sup>2=
</sup>)
=3D <span style=3D'color:red'>3.92 N</span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><o:p>&nbsp;</o:p></p>

<p class=3DCRPROB align=3Dleft style=3D'text-align:left;mso-pagination:none=
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lang=3DEN-AU style=3D'font-size:12.0pt;line-height:200%'>b.<span
style=3D'mso-spacerun:yes'>&nbsp; </span>How much work is done by friction =
on the
wood as the wood crosses the rough bottom?<o:p></o:p></span></p>

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b>fk</sub></span>
=3D (3.92 N<span class=3DGramE>)(</span>10.0 m)<span class=3DSpellE>cos</sp=
an>(180<sup>o</sup>)
=3D <span style=3D'color:red'>-39.2 J<o:p></o:p></span></p>

<p class=3DMsoNormal style=3D'text-align:justify'><o:p>&nbsp;</o:p></p>

<p class=3DCRPROB align=3Dleft style=3D'margin-left:0in;text-align:left;tex=
t-indent:
0in;mso-pagination:none'><span lang=3DEN-AU style=3D'font-size:12.0pt;line-=
height:
200%'>c. Where will this wood eventually come to rest?<o:p></o:p></span></p>

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'font-size:
12.0pt;line-height:200%'>W<sub>fk</sub> =3D E<sub>f</sub> &#8211; E<sub>i</=
sub> =3D
mgy<sub>f</sub> &#8211; mgy<sub>i</sub><o:p></o:p></span></p>

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'font-size:
12.0pt;line-height:200%'>mgy<sub>f</sub> =3D mgy<sub>i<span
style=3D'mso-spacerun:yes'>&nbsp; </span></sub>+W<sub>fk</sub> <o:p></o:p><=
/span></p>

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style=3D'mso-spacerun:yes'>&nbsp; </span></sub>+W<sub>fk</sub> /(mg) =3D <s=
pan
style=3D'color:red'>2.00 m</span><o:p></o:p></span></p>

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