TIME
OF COMPLETION_______________ &nb=
sp; NAME____SOLUTION=
_________________________
<=
span
style=3D'font-family:"Times New Roman"'>&nb=
sp; =
&nb=
sp; =
DEPARTMENT
OF NATURAL SCIENCES
PHYS 2211, Exam 2 =
&nb=
sp; =
&nb=
sp; =
&nb=
sp; =
&nb=
sp; Section
1
Version 1 &nb=
sp; =
&nb=
sp; =
&nb=
sp; =
&nb=
sp; =
October
24, 2008
Total
Weight: 100 points
1. =
Check
your examination for completeness prior to starting. There are a total of nine (9) prob=
lems
on six (6) pages.
2. =
Authorized
references include your calculator with calculator handbook, and the Refere=
nce
Data Pamphlet (provided by your instructor).
3. =
You
will have 50 minutes to complete the examination.
4. =
The
total weight of the examination is 100 points.
5. =
There
are six (6) multiple choice and three (3) calculation problems. Work all ca=
lculation
problems and 5 (five) multiple choice.&nbs=
p;
Show all work; partial credit will be given for correct work shown.<=
o:p>
6. =
If
you have any questions during the examination, see your instructor who will=
be
located in the classroom.
7. =
Start: &=
nbsp; 9:00
a.m.
Stop: &=
nbsp; 9:50
a.m.
|
&=
nbsp; &nbs=
p; PROBLEM
|
&=
nbsp; &nbs=
p; POINTS
|
&=
nbsp; &nbs=
p; CREDIT
|
|
&nbs=
p; &=
nbsp; 1-6
|
&nbs=
p; &=
nbsp; 25
|
&=
nbsp;
|
|
&nbs=
p; &=
nbsp; 7
|
&nbs=
p; &=
nbsp; 25
|
&=
nbsp;
|
|
8
|
&nbs=
p; &=
nbsp; 25
|
&=
nbsp;
|
|
&nbs=
p; &=
nbsp; 9
|
&nbs=
p; &=
nbsp; 25
|
&=
nbsp;
|
|
&=
nbsp; &nbs=
p; TOTAL
|
&=
nbsp; &nbs=
p; 100
|
|
|
|
&=
nbsp; PERCENTA=
GE
|
|
CIRCLE
THE SINGLE BEST ANSWER FOR ALL
MULTIPLE CHOICE QUESTIONS. IN MULTIPLE CHOICE QUESTIONS WHICH REQUIRE A
CALCULATION SHOW WORK FOR PARTIAL CREDIT.
- You=
throw
a ball straight up. Compare the sign of the work done by gravity on the
ball while the ball goes up with the sign of the work done by gravity
while it goes down.
a.<=
span
style=3D'font:7.0pt "Times New Roman"'> Work is positive on the way up and
positive on the way down.
b.<=
span
style=3D'font:7.0pt "Times New Roman"'> Work is positive on the way up and
negative on the way down.
(5)
c. Work is negative on the w=
ay up
and positive on the way down.
d.<=
span
style=3D'font:7.0pt "Times New Roman"'> Work is negative on the way up and
negative on the way down.
2. Two inclined frictionless planes A=
and B
have the same height but different angles of inclination. An object initial=
ly
at rest is released from the top of each of the inclined planes. How does t=
he
speed of the object at the bottom of the inclined plane A compare with that=
of
the speed at the bottom of the inclined plane B?
&nb=
sp;
- It is directly proportional t=
o the
angle.
- It is inversely proportional =
to the
angle.
(5)
- It is the s=
ame
for the both planes.
- There is not enough informati=
on to
answer the question.
3. A garbage truck crashes head=
-on
into a Volkswagen and the two come to rest in a cloud of flies. Which
experiences the greater impact force?
- T=
he
truck.
- T=
he
Volkswagen.
(5)
- B=
oth
experience the same force.
- N=
ot
enough information given.
=
4. If
the work done by all the external forces acting on an object is 5.80 J, and=
the
object
is
initially at rest, its final kinetic energy is
a. Zero.
b. 2.90 J
(5)
c. 5.80 J=
d. Cannot be determined.=
5. As an object is lowered into a deep hole in t=
he
surface of the earth, which of the following is true in regard to its
gravitational potential energy?
&nbs=
p; a.
Potential energy increases.
&nbs=
p; b.
Potential energy decrease=
s.
(5)
&nbs=
p; c.
Potential energy stays constant.
&nbs=
p; d.
Not enough information given.
.
6. A
particle moving along an x-axis is acted upon by a single force whose poten=
tial
energy function is pictured below. Which point(s) correspond to the state of
stable equilibrium?
<=
/p>
&nbs=
p; a. A and B.
&nbs=
p; b.
A and C.
(5)
&nbs=
p; c.
A, B and C.
&nbs=
p; d.
D.
&n=
bsp;
&n=
bsp;
&n=
bsp;
&n=
bsp;
&n=
bsp;
&nb=
sp;
&nb=
sp;
&nb=
sp;
&nb=
sp;
7. Consider a spring that does not obey Hooke’s=
law
very faithfully. One end of the spring is fixed. To keep the spring stretch=
ed
or compressed an amount of x, a=
force
along the x-axis with x-component of <=
/h1>
![](3D"Fall08.Phys2211.Exam2.SolutionWeb_files/image013.gif")
must be ap=
plied
to the free end. Here k =3D 100=
N/m, b =3D 700 N/m2, and c =3D 12,000 N/m3. Note=
that x > 0 when the spring is stretc=
hed
and x < 0 when it is compres=
sed.
a.
How much work must be done to stretch this spring by 0.0500 =
m from
its equilibrium position?
xi =3D 0, xf
=3D 0.0500 m
&nb=
sp;
&nb=
sp;
![](3D"Fall08.Phys2211.Exam2.SolutionWeb_files/image006.gif")
&nb=
sp;
&nb=
sp;
b.
How much work must be done to compress this spring by 0.0500=
m
from its equilibrium position?
xi =3D 0, xf
=3D -0.0500 m
&nb=
sp;
![](3D"Fall08.Phys2211.Exam2.SolutionWeb_files/image010.gif")
&nb=
sp;
&nb=
sp;
&nb=
sp;
&nb=
sp;
c. Is it=
easier
to stretch or compress this spring? (Many real springs behave qualitatively=
in
the same way)
&nb=
sp;
It is ea=
sier to
stretch this spring.
&nb=
sp;
&nb=
sp;
&nb=
sp;
8. &n=
bsp; A 2.00 kg package =
is
released on a 53.1o incline, 4.00 m from a long spring with force
constant of 120 N/m that is
attached to the bottom of the incline. The incline is fritionless. The mass=
of
the spring is negligible.
![](3D"Fall08.Phys2211.Exam2.SolutionWeb_files/image016.jpg")
a. &n=
bsp;
What is the speed of the package just before it reaches t=
he
spring?
Let’s
use the following notations: d =
=3D 4.00
m and final compression of the spring : xf
I
also choose to measure the gravitational potential energy from the position=
of
the block just before it reaches the spring.
&nb=
sp;
&nb=
sp;
&nb=
sp;
![](3D"Fall08.Phys2211.Exam2.SolutionWeb_files/image018.gif")
&nb=
sp;
![](3D"Fall08.Phys2211.Exam2.SolutionWeb_files/image020.gif")
&nb=
sp;
![](3D"Fall08.Phys2211.Exam2.SolutionWeb_files/image022.gif")
<=
/span>
Combining these eq=
uations:
![](3D"Fall08.Phys2211.Exam2.SolutionWeb_files/image024.gif")
![](3D"Fall08.Phys2211.Exam2.SolutionWeb_files/image026.gif")
Vf =3D 7.92 =
m/s
b. &n=
bsp; What is the maximum
compression of the spring?
&nb=
sp;
&nb=
sp;
![](3D"Fall08.Phys2211.Exam2.SolutionWeb_files/image029.gif")
=
&n=
bsp;
=
![](3D"Fall08.Phys2211.Exam2.SolutionWeb_files/image031.gif")
=
xf =3D 1.16 m
- Two blocks connected by a cord
passing over a small, frictionless pulley rest on frictionless planes.=
&nb=
sp;
![](3D"Fall08.Phys2211.Exam2.SolutionWeb_files/image032.jpg")
- Which way will the system mov=
e when
the blocks are released from rest?
&nb=
sp;
Down the=
30.0
degree incline.
&nb=
sp;
&nb=
sp;
&nb=
sp;
&nb=
sp;
- What is the acceleration of t=
he
blocks?
&nb=
sp;
![](3D"Fall08.Phys2211.Exam2.SolutionWeb_files/image017.jpg")
&nb=
sp;
100-kg b=
lock:
&nb=
sp;
&nb=
sp;
Tx =3D -T
Ty =3D 0
n1x =3D 0
n1y =3D n1
(m1g)x =3D m<=
sub>1g
sin(30.0o)
(m1g)y =3D - =
m1g
cos(30.0o)
&nb=
sp;
Second <=
st1:City
w:st=3D"on">Newton’s La=
w equations:
&nb=
sp;
&nb=
sp;
m1g sin(30.0o=
) - T =3D m1a<=
/span>
n1- m1g cos(3=
0.0o)
=3D 0, solving it:=
n1 =3D m1g cos(30.0o=
)
&nb=
sp;
&nb=
sp;
&nb=
sp;
50-kg bl=
ock:
&nb=
sp;
Tx =3D T
Ty =3D 0
n2x =3D 0
n2y =3D n2
(m2g)x =3D - =
m2g
sin(53.1o)
(m2g)y =3D - =
m2g
cos(53.1o)
Second <=
st1:place
w:st=3D"on">Newton’s Law=
equations:
&nb=
sp;
&nb=
sp;
T - m2g sin(53.1o) =3D m2a
n2- m2g cos(5=
3.1o)
=3D 0, solving it:=
n2
=3D m2g cos(53.1o)
&nb=
sp;
&nb=
sp;
&nb=
sp;
&nb=
sp;
Now let&=
#8217;s
work with the rest of the equations:
&nb=
sp;
m1g sin(30.0o=
) - T =3D m1a (1)
T - m2g sin(53.1o) =3D m2a (2)
&nb=
sp;
&nb=
sp;
From (2)=
:
&nb=
sp;
T =3D m2g sin(53.1o=
) + m2a
&nb=
sp;
Substitu=
ting it
into (1):
&nb=
sp;
m1g sin(30.0o=
) - m2g sin(53.1o) - m2a =3D m1a
(m1g sin(30.0o) - m2g sin(53.1o))/(
m1+ m2) =3D a
&nb=
sp;
a =3D 0.654 m/s2
&nb=
sp;
&nb=
sp;
&nb=
sp;
&nb=
sp;
- What is the tension in the co=
rd?
T =3D m2g sin(53.1o=
) + m2a
T =3D 425 N
=
------=_NextPart_01C95312.937DC620
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