MIME-Version: 1.0 Content-Type: multipart/related; boundary="----=_NextPart_01C83A68.423F17A0" This document is a Single File Web Page, also known as a Web Archive file. If you are seeing this message, your browser or editor doesn't support Web Archive files. Please download a browser that supports Web Archive, such as Microsoft Internet Explorer. ------=_NextPart_01C83A68.423F17A0 Content-Location: file:///C:/D9286902/Fall07.phys1112.exam3.SolutionWeb.htm Content-Transfer-Encoding: quoted-printable Content-Type: text/html; charset="us-ascii" TIME OF COMPLETION_______________

TIME OF COMPLETION_______________&n= bsp;           NAM= E___SOLUTION__________________________

 

 

<= span style=3D'mso-bidi-font-size:10.0pt'> &= nbsp;           &nbs= p;            &= nbsp;           &nbs= p;    DEPARTMENT OF NATURAL SCIENCES

 

PHYS 1112, Exam 3            =             &nb= sp;            =             &nb= sp;            =             &nb= sp;            =             &nb= sp;  Section 1

Version 1            &= nbsp;           &nbs= p;            &= nbsp;           &nbs= p;            &= nbsp;           &nbs= p;            &= nbsp;           &nbs= p;     December 3, 2007

Total Weight: 100 points

 

1.     &nb= sp;   Check your examination for completeness prior to starting.  There are a total of ten (10) prob= lems on seven (7) pages.

 

2.   =       Authorized references include your calculator with calculator handbook, and the Refere= nce Data Pamphlet (provided by your instructor).

 

3.     &nb= sp;   You will have 50 minutes to complete the examination.

 

4.     &nb= sp;   The total weight of the examination is 100 points.

 

5.     &nb= sp;   There are six (6) multiple choice and four (4) calculation problems. Work five (5) multiple choice problems and three (3) calculation problems. Show all work; partial credit will be given for correct work shown.

 

6.     &nb= sp;   If you have any questions during the examination, see your instructor who will=

be located in the classroom.

 

7.     &nb= sp;   Start:        &= nbsp;      11:30 a.m.

Stop:&n= bsp;            = ;   12:20 p.m.

 

 

 

 = ;             <= /span>PROBLEM

 

 = ;            &n= bsp;   POINTS

 

 = ;            &n= bsp;  CREDIT

 

     &nb= sp;            =    1-6

 

     &nb= sp;            =    25

 

 = ;

 

     &nb= sp;            =     7

 

     &nb= sp;            =    25

 

 = ;

 

8

 

     &nb= sp;            =    25

 

 = ;

 

     &nb= sp;            =     9

 

     &nb= sp;            =    25

 

 = ;

 

 = ;            &n= bsp;       10

 

 = ;            &n= bsp;       25

 

 

 

 = ;            &n= bsp;   TOTAL

 

 = ;            &n= bsp;      100

 

 

 

 

 

 = ;          PERCENTAGE

 

 

 

CIRCLE THE SINGLE BEST ANSWER FOR ALL MULTIPLE CHOICE QUESTIONS. IN MULTIPLE CHOICE QUESTIONS WHICH REQUIRE A CALCULATION SHOW WORK FOR PARTIAL CREDIT.

 

 

 

1.&n= bsp;    A resistor is connected to an AC supply. On t= his circuit, the current

a.&n= bsp;     Leads the voltage by 90o.

b.&n= bsp;    Lags the voltage by 90o.

c.&n= bsp;     Is in phase with the voltage.=

d.&n= bsp;    Leads the voltage by 180o.

 

 

     2.  The inductive reactance in an ac c= ircuit changes by what factor when the frequency is tripled?

 

  &nbs= p;            &= nbsp;            a. 1/3.

 

  &nbs= p;            &= nbsp;            b. 1/9.

 

  &nbs= p;            &= nbsp;            c. 3.

 

  &nbs= p;            &= nbsp;            d. 9.

 

 

3.&n= bsp;    Which one of the following is the correct ord= er of the electromagnetic spectrum from low to high frequencies?

a.&n= bsp;     Radio waves, infrared, microwaves, UV, visibl= e, X-rays, gamma rays.

b.&n= bsp;    Radio waves, UV,  X-rays, microwaves, infrared, visi= ble, gamma rays.

c.&n= bsp;     Radio waves, microwaves,  infrared,  visible, UV, X-rays, gamma rays.

d.&n= bsp;    Radio waves, microwaves,  visible, X-rays, infrared, UV, gam= ma rays.

&= nbsp;

 

 

4.&n= bsp;    The frequency of a microwave sygnal is 9.76 G= Hz. What is its wavelength in meters?

a.&n= bsp;     3.07 x 10-2 m.

b.&n= bsp;    2.07 x 10-2 m.

c.&n= bsp;     1.07 x 10-2 m.

d.&n= bsp;    5.07 x 10-2 m.

&= nbsp;

&= nbsp;

5.&n= bsp;    Which of the following is a correct statement= ?

a.&n= bsp;     A concave mirror always produces a real image= .

b.&n= bsp;    A convex mirror always produces a virtual image= .

c.&n= bsp;     A convex mirror always produces a real image.=

d.&n= bsp;    A concave mirror always produces a virtual im= age.

&= nbsp;

&= nbsp;

6.&n= bsp;    Which of the following is correct for a convex mirror?

a.&n= bsp;     f =3D (= 1/4)R.

b.&n= bsp;    f =3D (= 1/2)R.

c.&n= bsp;     f= =3D - (= 1/2)R.

d.&n= bsp;    f =3D 2= R.

&= nbsp;

        &= nbsp;

 

 

        7. A 400-mH inductor with 200 W resistance is connected in series to a 5.00 mF capacitor and a 60-Hz, 30-V source. Calculate

 

 

a. The impedance of the circuit.

 

XL =3D = 2 p f L =3D 2 p (60.0 Hz) (400 x 10-3 H) =3D 151 W

 

XC =3D = 1/(2 p= f C) =3D 1/(2 p (60.0 Hz) (5.00 = x 10-6 F)) =3D 530 W

 

Z =3D (R2 + (XL – XC)2)1/2 =3D ((200 W)2 + (151 W  – 530 W)2)1/2   =3D 429 W

 

 

 

b. The rms current that flows in the inductor.

 

Irms =3D DVrms /Z

 

Irms =3D (30.0 V)/(429 W) =3D 0.0700 A

 

 

c. The phase angle.

 

f =3D tan-1 ((XL – XC)/R)

 

f =3D tan-1 ((151 W R= 11; 530 W)/ (200 W)) =3D -62.2o

 

 

 

        =     d. Does the voltage in the inductor lead the voltage in the capacito= r or lags behind?

 

 

Voltage in the inductor makes= 180o angle with the voltage in the capacitor.

 

 

        =      e. What is the resonant frequency of this circuit?

 

X= L =3D XC

 

2 p f0 L =3D 1/(2 p f0 C)

 

f0 =3D 1/(2 p Sqrt (LC<= span style=3D'font-family:Symbol'>))=3D 110 Hz

 

8. An incident ray makes an angle of 60o with the normal to the bounda= ry between water (n =3D 1.33) and glass (n =3D 1.52). What is the angle betwee= n the reflected and refracted rays?

 

 

n1 sin(q1) =3D n2 sin(q2) 

   <= /p>

sin(q2) =3D (1.33) sin(60.0o)/(1.52) =3D 0.758 

 

q2 =3D 49.2o

 

 q =3D 180o – (49.2o + 60.0o) =3D 70.8o

 

 

9.Santa checks him= self for soot, using his reflection in a shiny silvered Christmas tree ornament 25.0= cm away. The diameter of the ornament is 7.20 cm. Standard reference works sta= te that he is a “right jolly old elf”, so we estimate his height t= o be 1.60 m.

 <= /span>

 a. Where is the image of Santa form= ed by the ornament?

do=3D 25.0 cm

 

f =3D - 1.80 cm

 

1/di + 1/do=3D 1/f

 

1/di =3D 1/f - 1/do =3D 1/(-1.80 cm) - 1/(25.0 cm) =3D -0.596 cm-1 <= /p>

 

di =3D<= span style=3D'mso-spacerun:yes'>  -1.68 cm=

b. How tall is the= image?

M =3D - di /do =3D -(-1.68 cm)/(25.0 cm) =3D  0.0671

 

hi=3D M= ho=3D 0.107 m=

c. Is the image up= right or inverted?

Upright (M > 0)

d. Is the image re= al or virtual?

Virtual = (di < 0)

 <= /span>

 <= /span>

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

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PHYS 1112 Exam 3, Version 1

Fall 2007        =             &nb= sp;            =             &nb= sp;            =             &nb= sp;    7

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