MIME-Version: 1.0 Content-Location: file:///C:/D9286902/Fall06.Phys1112.Quiz10.SolutionWeb.htm Content-Transfer-Encoding: quoted-printable Content-Type: text/html; charset="us-ascii" Department of Natural Sciences

 

Clayton State University

Department = of Natural Sciences

November 27, = 2006

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Physics 111= 2 – Quiz 10

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 =

Name  ___SOLUTION__________________________________

 

A lens forms an image of = an object. The object is 60.0 cm from the lens. The image is 20.0 cm from the = lens on the same side as the object= .

 

<= span style=3D'mso-list:Ignore'>a.&n= bsp;     What is the focal length of the lens?

 

do =3D 60.0 cm

 

di =3D -20.0 cm

 

1/di + 1/do =3D 1/f

 

1/f  =3D 1/(60.0 cm) + 1/(-20.0 cm) =3D - 2/(60.0 cm)

 

f =3D -30.0 cm

 

<= span style=3D'mso-list:Ignore'>b.&n= bsp;    Is the lens converging or diverging?

 

Diverging (f < 0)

 

<= span style=3D'mso-list:Ignore'>c.&n= bsp;     If the object is 10.0 cm tall, how tall is the imag= e?

 

M =3D - di /do =3D - (-20.0 cm)/(60.0 cm) =3D 0.= 333

 

hi =3D M ho =3D (0.333)(10.0 cm) =3D 3.33= cm

 

 

<= span style=3D'mso-list:Ignore'>d.&n= bsp;    Is the image upright or inverted?

 

Upright (M > 0)