Department of Natural Sciences

Clayton College & State University

October 20, 2003

Physics 1112 – Quiz 7

Name __SOLUTION___________________________________

1. A 1.00-m long wire is held horizontally in the uniform magnetic field with the strength of 0.200 T directed as shown below. The wire is then lowered vertically at a rate of 0.600 m/s.

1. What voltage will appear across the wire?

e = V B L = (0.600 m/s)(0.200 T) (1.00 m) = 0.120 V

2. Which end will be positive?

Right.