Department of
Natural Sciences
Clayton College & State University
Morrow, Georgia
February 10, 2009
SCI 1901E - Quiz 6
Name __________SOLUTION_____________
(09) 1. Calculate the R-value for a wall of the following composition: 1/2" lapped wood siding, 2" hardwood plank, 4" of cellulose insulation and 1/2" sheetrock wall board. A table of R-values is provided below:
material |
thickness |
R-value |
hardwood |
1" |
0.91 |
softwood |
1" |
1.25 |
plywood |
1/2" |
0.62 |
sheetrock |
1/2" |
0.45 |
fiberglass insulation |
3 1/2" |
10.9 |
fiberglass insulation |
6" |
19.0 |
cellulose insulation |
1" |
3.7 |
wood sliding (lapped) |
1/2" |
0.81 |
Rtotal = Rlw + Rhp + Rci + Rsr
Rtotal = [ (0.81) + (2)(0.91) + (4)(3.7) + (0.45) ] ft2·hr·°F/Btu
Rtotal = 17.88 ft2·hr·°F/Btu ANS
(06) 2. If the wall in problem 1 has dimensions of 15.0 ft by 8.0 ft, calculate rate of heat transfer by conduction through the wall when the indoor temperature is 70°F and the outdoor temperature is 20°F.
Awall = (15.0 ft)(8.0 ft) = 120 ft2
DT = 70°F - 20°F = 50°F
Qc / t = A DT / R
Qc / t = (120 ft2)(50°F) / (17.88 ft2·hr·°F/Btu)
Qc / t = 336 Btu / hr ANS