Homework Solution

TP 6-3

Given:

        insolation = 850 W/m²

        collection efficiency = 0.20

        required power = 240 W

Find:

        required area

Science:

        P_Q = IeA

Solve:

        A = P_Q /(Ie)

        A = (240 W)/[(850 W/m²)(0.2)]

        A = 1.41 m²