Homework Solution

TP 4-10

Given:

    Heat engine with:

        T_H = 30 ^oC

         T_C = 10 ^oC

Find:

    maximum efficiency of the heat engine

Science:

e_max = (1 - T_C /T_H) x 100%

where the temperatures must be expressed in kelvins

Solve:

 T_H = 273 K + 30 K = 303 K

T_C = 273 K + 10 K = 283 K

e_max = (1 - 283 K / 303 K) x 100%

e_max = 6.6%_ANS