Homework Solution
TP 4-2
Given:
12 gallons of water
DT
= 130 oF - 50 oF = 80 oF
cost of electricity = $0.08/kWh
Find:
heat energy required to change the temperature
cost for the temperature rise
Science:
DQ = mc DT
Solve:
m = (12 gal)(8.3 lb/gal) = 99.6 lb
c = 1.00 Btu/(lb oF)
Q = (99.6 lb)(1.00 Btu/(lb oF))(80 oF)
Q = 7986 Btu
1 kWh = 3413 Btu
Cost = (7986 Btu)(1 kWh/(3413 Btu))($0.08/kWh)
Cost = $0.187