TP 4.34

Given:

x₀ = 0,  y₀ = 0, x = 3.80 m  (assuming that the origin of your coordinate system is located at the level the ball is hit)

q = 34.0^o 

v₀ = 14.0 m/s                

Find:         (a) t    (b) y

Physics:    projectile motion

Solve:

v_0x = v₀ cosq = (14.0 m/s) cos(34.0^o) = 11.60653 m/s

v_0y = v₀ sinq = (14.0 m/s) sin(34.0^o) = 7.82870 m/s

x = x₀ + v_0x t

x = v_0x t

t = x /v_0x = (3.80 m)/(11.60653 m/s)  = 0.32740 s = 0.327 s

                           

y = y₀ + v_0yt – ½ g t²

y = v_0yt – ½ g t² = (7.82870 m/s) (0.32740 s) - ½ (9.81 m/s2) (0.32740 s)² = 2.04 m